A small bead of mass m = 3.33 g is attached to a light (massless), inextensible string which passes through a hole in a flat tabletop. At the other end of the string, a larger mass M = 0.0156 kg is attached to the string and hangs freely below the tabletop, however, it is initially supported by sitting on a shelf. Initially, the length of string connecting the small bead to the hole in the tabletop is effectively a radius, r = 0.201 m. The small bead is then set into uniform circular motion with an initial velocity v = 1.04 m/s perpendicular to the string and in the plane of the tabletop. Assume that there are no frictional forces between the small bead and the tabletop and no friction between the string and the hole in the tabletop. Part 1 What is the magnitude of the centripetal force required to maintain the uniform circular motion of the small bead? F. = IN What is the angular momentum of the small bead? L = kgm's-1 Part 2) The heavier mass, M = 0.0156 kg, that is attached to the opposite end of the string is released from the shelf supporting it so that it now hangs freely below the tabletop. What is the magnitude of the net force on the larger hanging mass immediately after it has been released? IFI = N Part 3) The heavier mass starts to fall but eventually comes to rest, still hanging from the string. Is the angular momentum of the small bead conserved in this situation? (No answer given) + What is the radius of the string connecting the small bead to the hole in the tabletop when the larger mass comes to rest (equilibrium)