- A solution is created by dissolving 13.5 grams of ammonium chloride in enough water to make 335 mL of solution. How many moles of ammonium chloride are present in the resulting solution?

- When thinking about the amount of solute present in a solution, chemists report the concentration or molarity of the solution. Molarity is calculated as moles of solute per liter of solution. What is the molarity of the solution described above?

- To carry out a particular reaction, you determine that you need 0.0500 moles of ammonium chloride. What volume of the solution described above will you need to complete the reaction without any leftover NH₄Cl?

A solution is created by dissolving 13.5 grams of ammonium chloride in enough water to make 335mL of solution. How many moles of ammonium chloride are present in the resulting solution? molesofNH4Cl Part 2 (1 point) See Hint When thinking about the amount of solute present in a solution, chemists report the concentration or molarity of the solution. Molarity is calculated as moles of solute per liter of solution. What is the molarity of the solution described above? M Part 3 (1 point) See Hint To carry out a particular reaction, you determine that you need 0.0500 moles of ammonium chloride. What volume of the solution described above will you need to complete the reaction without any leftover NH4Cl ? mL of solution