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A solution was prepared by mixing benzene (C6H6) and carbon tetrachloride (CCL). Given that the mole fraction of carbon tetrachloride is 0.848 in the solution

A solution was prepared by mixing benzene (C6H6) and carbon tetrachloride (CCL). Given that the mole fraction of carbon tetrachloride is 0.848 in the solution obtained from 4.67 mol CCl4, calculate the moles of benzene used. mol

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