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A solvent contaminated with 0.03 kmol/m of a fatty acid is to be purified by passing it through a fixed bed of activated carbon which
A solvent contaminated with 0.03 kmol/m of a fatty acid is to be purified by passing it through a fixed bed of activated carbon which will adsorb the acid but not the solvent. If the operation is essentially isothermal and equilibrium is maintained between the liquid and the solid, calculate the length of a bed of 0.15 m diameter to give 3600 s (1 h) of operation when the fluid is fed at 1 x 104 m/s. The bed is initially free of adsorbate, and the intergranular voidage is 0.4. Use an equilibrium, fixed-bed theory to obtain an answer for three types of isotherm: (a) C, 10 C (b) Cs 3.0 C0.3 use the mean slope (c) C, 104 C take the breakthrough concentration as 0.003 kmol/m. C and C, refer to concentrations (kmol/m) in the gas phase and the adsorbent, respectively.
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