A study was conducted by the department of zoology at the Virginia tech to estimate the difference in the amount of the chemical orthophosphorus measured at two different stations on the James river. Orthophosphorus was measured in milligrams per liter. fifteen specimen were collected from station 1, and 12 specimens were obtained from station 2. the 15 specimens from station 1 had an average orthophosphorus content of 3.84 milligrams per liter and a standard deviation of 3.07 milligrams per liter, while the 12 specimens from station 2 had an average content of 1.49 milligrams per liter and a standard deviation of 0.8 milligrams per liter. Assume the observations came from normally distributed populations with different variances. what formula should be used in order to find. a 96% confidence interval for the difference jn the true average orthophosphorus contests at those two stations? Are the assumptions satisfied for using the formula ?

QUESTION 2 #1 continued. Compute a 96% confidence interval for the difference in the true average orthophosphorus contests at those (0.6544, 4.0456) (0.3715, 4.3285) 0.3715