a. Suppose that $3,373 amounted to $6,737 in a savings account after 22 years. If the interest was compounded monthly, find the nominal (yearly) rate of interest earned by the money.Enter your answer as a decimal with 4 digits after the dot (for example 0.0271 (which corresponds to 2.71% annular percentage)).

b. what is the formula used above. base this answer off the photo I will attach.

it is a choice between these

S = P(1+r)" 5.1a P = S(1 +r)" 5.2a 5.4d Solve for P: P = S 5.1b (1+r)" A = R(1 + an=Ir) NOTE it is (n-1), not n Solve for r: (1+r)" = S (1 +r)" - 1 Spar E 5.4e S r 1+r= D S = Per 5.3a S S = RSar 5.4f 5.1c Te=e- 5.3b Solve for n: (1+r)" = S S = R(S,+1lr = 1) NOTE the (n+1) instead of n 5.4g P P = Se 5.3c In(1 + r)" = In- S P 5.4h In S Snir P n= 5.1d In(1 + r) Table 5.2 Amortization Formulas 1 - (1+r) 1. Periodic payment: R - an, = 5.4a 1 - (1 +r)-" 5.5a re ( 1 + ")" -1 5.1e 2. Principal outstanding at beginning of kth period: A = Ran, 5.4b 5.5b A R = 3. Interest in kth payment: Rram_k+1, 5.5c 5.4c anr 4. Principal contained in kth payment: R(1 - ram_k+1,) 5.5d 5. Total interest paid: R(n - a; ) = nR -A 5.5e