A system can go to one of $6$ states s$0,$ s$1,...,$ s$5.$ A set of $4$ events: A$,$B$,$ C &D can force the system to change its state as shown in the state diagram below:An event generator generates the events according to the following algorithm:$1.$ Generate the following event sequence: A$,$B$\mathrm{.}2.$ If the state is s$0$ or s$1$ or s$3$ then go to step $4\mathrm{.}3.$ Generate the following event sequence A$,$B$,$C$,$D$\mathrm{.}4.$ If the state is S$0$ or S$1$ or S$4$ then go to step $6\mathrm{.}5.$ Generate the following event sequence A$,$B$,$C$,$D$\mathrm{.}6.$ If the state is SO or S$1$ then go to step $1\mathrm{.}7.$ Stop$\mathrm{.}1-$ Suppose the system is initially at state SO$.$ Apply the above algorithm. What will be the state of the system when you reach step $7.$Answer:$2-$Suppose the system is initially at state $51.$ Apply the above algorithm. What will be the state of the system when you reach step $7$Answer:$3-$ Suppose the system is initially at state $52.$ Apply the above algorithm. What will be the state of the system when you reach step $7.$Answer:$4-$Suppose the system is initially at state S$3.$ Apply the above algorithm. What will be the state of the system when you reach step $7.$Answer:$5-$Suppose the system is initially at state S$4.$ Apply the above algorithm. What will be the state of the system when you reach step $7.$Answer:$6-$Suppose the system is initially at state S$5.$ Apply the above algorithm. What will be the state of the system when you reach step $7.$Answer:$7-$Suppose there is a hardware bug in the event generator, so that it can not generate event A$.$ Suppose that the system is initially at state SO$.$ Apply the above algorithm. What will be the state of the system when you reach step $7.$Answer:$8-$Suppose there is a hardware bug in the event generator, so that it can not generate event B$.$ Suppose that the system is initially at state SO$.$ Apply the above algorithm. What will be the state of the system when you reach step $7.$Answer: