A system has three particles A, B and C. The masses of these particles are ma = 2 kg, m3 = 3 kg and mc 3 kg. For particle A, position vector A = 4 +19+2k with velocity vector VA= - 51 - 59+ l. For particle B, position vector B = -51 +23+ 3k with velocity vector vb = 1 +49 + 3k. For particle C, position vector Fc = - 31 - 23 + 1 with velocity vector vc = 4 +59 +1. Find the angular momentum about the center of mass (sometimes called center of gravity). HG= + 9 + with units of Question Help: Written Example Submit