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A tachyon is a hypothetical particle that travels faster than light. Suppose we have a tachyon that is moving at u = 2.900c in
A tachyon is a hypothetical particle that travels faster than light. Suppose we have a tachyon that is moving at u = 2.900c in the +x direction. It is emitted from the origin at x = 0 at t = 0 and is absorbed at t = 3.30 ns. (a) What is the coordinate x when the particle stops? m (b) Show that there is a velocity v, less than the speed of light, such that according to that observer, the tachyon is moving at infinite velocity. What is that velocity v, as a fraction of the speed of light c? (c) Consider what the tachyon would look like to an observer moving at velocity v = 0.710cWhat are the coordinates of the absorption event x' and t', as observed by the moving observer? x = t' = m ns Note that according to this observer, the tachyon was absorbed before it was emitted. This is one of many reasons that most physicists don't believe tachyons exist. Joe the Experimenter decides to test relativity as follows. He sets up a laser in the rest frame so that it is pointed in the negative x- direction, but at an angle = 39.0 degrees compared to the x-axis. He then moves in the +x-direction at velocity v = 0.800c. (a) What is the velocity vector of the light beam in the unmoving reference frame, as a fraction of the speed of light? U = ci+ cj (b) What is the velocity vector of the light beam as measured by Joe, as a fraction of the speed of light? u' = ci+ cj (c) What is the magnitude of the velocity of this light beam, as measured by Joe, as a fraction of the speed of light? Joe P Laser beam
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a To find the coordinate x when the tachyon stops we can use the equation of motion for the tachyon ...Get Instant Access to Expert-Tailored Solutions
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