Answered step by step
Verified Expert Solution
Question
1 Approved Answer
(a) TimecG'h T = kcG'h Putting the dimensions in the above relation [MLT]=[LT]*[M'[M T [MLT]=[M+x+3y+2=-x-2y=] Comparing the powers of M, L and T -y+==0
(a) Timec"G'h T = kcG'h Putting the dimensions in the above relation [MLT]=[LT]*[M'[M T [MLT]=[M+x+3y+2=-x-2y=] Comparing the powers of M, L and T -y+==0 x+3y+2==0 -x-2y-==1 ....(i) (ii) (iii) On solving equations (i) and (ii) and (iii) -5 x = 2 2 Hence, dimension of time are [G1/2 1/2-5/2].
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started
Discrete and Combinatorial Mathematics An Applied Introduction
Authors: Ralph P. Grimaldi
5th edition
201726343, 978-0201726343
