A train is 100 km due east of a car at 4:00 P.M. The car travels due north at a rate of 60 km/h and the 6. train travels due west at a rate of 70 km/h. At what rate is the distance between them changing at b) 6:30 P.M. ? a) 5:00 P.M. ? 100 km 2 (100 . 10 x x 1 = 70 kalh y' = bokmath X = 100 + x 2 (30 ) (70)+ 2 (10)Cho) =(00- 70) 170326016 0) * STAR OR DOWN