A uniform bar, of mass MM, with seven evenly spaced holes is held by sliding the bar over a horizontal peg

through one of the seven holes. The peg passes through hole C, and a cylinder hangs from a hook placed through

hole B as shown above. The mass of the bar is equal to the mass of the cylinder, and the location of the center of

mass of the bar is at the center of hole D. In this configuration, the bar-cylinder system remains motionless but is

free to rotate around the peg in hole C. Frictional forces acting on the bar are negligible.

(a) Two additional cylinders, identical to the one shown, can each be hung on the bar by hooks from any of the

open holes so that the bar will still be in rotational equilibrium when all three cylinders are hanging from it. From

which two holes should the two cylinders be hung? Briefly explain your reasoning.