A uniform, horizontal beam of length and mass M is pivoted on the wall at one end (A) and connected to the ceiling by a wire at the other end (B). A metal advertising sign of mass m is suspended from the beam at 0.65 L as shown in the figure. a) Draw a free-body diagram of the beam and show all forces acting on it. Call the tension in the wire as FT and the components of the force exerted by the pivot A on the beam as Fx and Fy b) Write down the three conditions for equilibrium. M 0.65 L- tg m B c) By using above equations, find the tension in the wire (FT) in terms of all or some of M, m, and g. d) Find the components (Fx and Fy) of the force exerted by the pivot A on the beam, in terms of some or all of M, m, and g. e) M = 19 kg, m = 10 kg, L = 5.0 m, and = 53 are given. Using the above equations calculate FT, Fx and Fy.