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(a.) Using the pumping lemma for context-free languages, prove that {a^n b^m c^n|m greaterthanorequalto n) is not a CFL. (b.) Let A = {x |

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(a.) Using the pumping lemma for context-free languages, prove that {a^n b^m c^n|m greaterthanorequalto n) is not a CFL. (b.) Let A = {x | x belongsto {a, b, c}* and x contains the same number of each of the three symbols}. Using the pumping lemma for context-free languages, prove that A is not a CFL

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