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A vertical force of 1 0 kN was applied to 2 - 7 curtains of the two - faced section shown in the figure. Flange

A vertical force of 10 kN was applied to 2-7 curtains of the two-faced section shown in the figure. Flange areas
300 mm2, stringer areas are 100 mmekilde grlen iki yzl kesitin 2-7 perdesine 10 kN'luk dey bir kuvvet uygulanmtr. Flanj alanlar
300mm2, stringer alanlar100mm2 'dir. 2 ve 7'de ikier tane flanj vardr. Cidar kalnl1 alt ve st duvarlarda
1mm, yan duvarlarda 2mm 'dir. 10kN 'luk kuvvet nedeniyle tm duvarlarda oluan kayma aklarn bulunuz.
Not: Kesiti nce idealletiriniz. Kesmeleri 1-2 ve 2-3 duvarlarndan yapnz.
Bi=tb6(2+ji)
qs=-(SxI-SyIxyIIyy-Ixy2)(0stDx(d)s+r=1nBrxr)
-(SyIyy-SxIxyIIyy-Ixy2)(0stDy(d)s+r=1nBryr)+qs,0
ddz=12ARGoRqdst
Sx0-Sy0=R=1NMq,R=R=1NoRqbp0ds+R=1N2ARqs,0,R2. There are two flanges each at 2 and 7. Wall thickness on upper and lower walls
1 mm,2 mm on the side walls. Find the shear fluxes occurring on all walls due to the 10 kN force.
Note: Idealize the section first. Make the cuts on walls 1-2 and 2-3. PLEASE CALCULATE BY HAND!!
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