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A Volleyball is thrown up with a velocity of 10 m/s, from a third floor (15Meters above the ground) at angle of 45 from horizontal.

A Volleyball is thrown up with a velocity of 10 m/s, from a third floor (15Meters above the ground) at angle of 45 from horizontal. The ball went up for a while and landed on the ground 15meter from the place of launch. a) How high the ball rouse from the place of launch? Vyi = Vi * sin(45) = and Vxi= Vi*cos(45) = Vy,max=0 on the top, Vf=0=Vyi + a*t = Vyi - g*t distance travel up ymax= Vi *t + *g*t2 = Ytotal = Yintial +Ymax= b) How long the ball took before hitting the ground? Free fall from Ytotal ytotal = g*t2 Total time= time-up + time-down = 0.72 + 1.89 = 2.61seconds c) How far away the ball will land from the building? The horizontal velocity is constant, then total displacement Dx = Vxi * t-total =

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