A weight W is supported by two cables anchored a distance D apart (see Figure P35) The cable length L AB is given, but the length L AC is to be selected Each cable can support a maximum tension force equal to W For the weight to remain stationary, the total horizontal force and total vertical force must each be zero This principle gives the equations T AB cos theta T AC cos phi 0 T AB sin theta T AC sin phi W We can solve these equations for the tension forces T AB and T AC if we know the angles theta and phi From the law of cosines theta cos 1 (D 2 L 2 AB L 2 AC 2DL AB) From the law of sines phi sin 1(L AB sin theta L AC) For the given values D 6 ft, L AB 3 ft, and W 2000 lb, use a loop in MATLAB to and L ACmin, the shortest length L AC we can use without T AB or T AC exceeding 2000 lb Note that the largest L AC can be is 6 7 ft (which corresponds to theta 90 degree) Plot the tension forces T AB and T AC on the same graph versus L AC for L ACmin lessthanorequalto L AC lessthanorequalto 6 7 A weight W is supported by two cables anchored a distance D apart (see Figure P35) The cable length L AB is given, but the length L AC is to be selected Each cable can support a maximum tension force equal to W For the weight to remain stationary, the total horizontal force and total vertical force must each be zero This principle gives the equations T AB cos theta T AC cos phi 0 T AB sin theta T AC sin phi W We can solve these equations for the tension forces T AB and T AC if we know the angles theta and phi From the law of cosines theta cos 1 (D 2 L 2 AB L 2 AC 2DL AB) From the law of sines phi sin 1(L AB sin theta L AC) For the given values D 6 ft, L AB 3 ft, and W 2000 lb, use a loop in MATLAB to and L ACmin, the shortest length L AC we can use without T AB or T AC exceeding 2000 lb Note that the largest L AC can be is 6 7 ft (which corresponds to theta 90 degree) Plot the tension forces T AB and T AC on the same graph versus L AC for L ACmin lessthanorequalto L AC lessthanorequalto 6 7

Question

A weight W is supported by two cables anchored a distance D apart (see Figure P35)  The cable length L AB is given, but the length L AC is to be selected  Each cable can support a maximum tension force equal to W  For the weight to remain stationary, the total horizontal force and total vertical force must each be zero  This principle gives the equations  T AB cos theta   T AC cos phi   0 T AB sin theta   T AC sin phi   W We can solve these equations for the tension forces T AB and T AC if we know the angles theta and phi  From the law of cosines theta   cos  1 (D 2  L 2 AB   L 2 AC 2DL AB) From the law of sines phi   sin  1(L AB sin theta L AC) For the given values D   6 ft, L AB   3 ft, and W   2000 lb, use a loop in MATLAB to and L ACmin, the shortest length L AC we can use without T AB or T AC exceeding 2000 lb  Note that the largest L AC can be is 6 7 ft (which corresponds to theta   90 degree)  Plot the tension forces T AB and T AC on the same graph versus L AC for L ACmin lessthanorequalto L AC lessthanorequalto 6 7  A weight W is supported by two cables anchored a distance D apart (see Figure P35)  The cable length L AB is given, but the length L AC is to be selected  Each cable can support a maximum tension force equal to W  For the weight to remain stationary, the total horizontal force and total vertical force must each be zero  This principle gives the equations  T AB cos theta   T AC cos phi   0 T AB sin theta   T AC sin phi   W We can solve these equations for the tension forces T AB and T AC if we know the angles theta and phi  From the law of cosines theta   cos  1 (D 2  L 2 AB   L 2 AC 2DL AB) From the law of sines phi   sin  1(L AB sin theta L AC) For the given values D   6 ft, L AB   3 ft, and W   2000 lb, use a loop in MATLAB to and L ACmin, the shortest length L AC we can use without T AB or T AC exceeding 2000 lb  Note that the largest L AC can be is 6 7 ft (which corresponds to theta   90 degree)  Plot the tension forces T AB and T AC on the same graph versus L AC for L ACmin lessthanorequalto L AC lessthanorequalto 6 7

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A weight W is supported by two cables anchored a distance D apart (see Figure P35). The cable length L_AB is given, but the length

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