A year in the modern Gregorian Calendar consists of $365$ days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every $4$ years, a leap year takes place. Read this article if you want to learn more about the history and science behind leap days$/$years$.$

Specifically, a leap year is when a year has $366$ days: An extra day, February $29$th$.$ The requirements for a given year to be a leap year are:

$1)$ The year must be divisible by $4$

$2)$ If the year is a century year $(1700,1800,$ etc.$),$ the year must be evenly divisible by $400$

Some example leap years are $1600,1712,$ and $2016.$

Write a free$-$standing function bool isLeapYear$($ unsigned int inputYear$)$; that takes in a year $($i$.$e$.,$ inputYear$)$ and determines whether that year is a leap year.

Example $1$: If inputYear is $1712,$ the above function will return true since $1712$ is a leap year.

Example $2$: If the inputYear i $"$s $1913,$ the above function will return false since $1913$ is not a leap year.

Your code needs to include

$-$ a function isLeapYear$()$ that returns true$/$false given a year.

$-$ Three unit tests test$1(),$ test$2(),$ and test$3(),$ each of which returns true

if isLeapYear$()$ returns the correct answer on three different inputs of your choice.

For example:

bool test$1()$

$\{$

return $($isLeapYear$(2000)==$true$)$

C$++$