a20 = 198 + (20-1) d all : 56+1 20-/117d # 117 6 6 d -117 - 117 - 97 / = d Sn = In [zo 200 = at ( 20-1)d Sy = 1x 4 [ 2 x 2 S20 = intatL) th(2a (n-i)d] Sy = 2 [ 196 + 3 $ 5203 +x 20[ 20+ (n-old ] Sy = 2 [ 199 d ) S20= 10 [20+ 20-1d] 4- 398d 4 A sequence is given by x, =4, X,,41 = px,, -9 where p is an integer. 0-10/20+19]a Show that x, = 4p - 9p-9 b Given that x3 = 46, find the value of p. c Hence find the value of X5 . 2124 In+1 = pacn- q SI= = [ 2 xy+ 2 + 1 / pac - 9 24- pac - 10 SI= yd ) - 26 2 + 1 = P2 2 - 9 63 - 46 = up*- 9 p- 9 Pearson Edexcel AS anPure Mathematics Year 2 (A Level) Tutor Card 1 Test Name: 2 f(x)= x +25x+16 9x2 - 16 B C Show that f(x) can be written in the form A+ -+ , where A, B and C 3x - 4 3x + 4 are constants to be found. (7 marks) A + B 12 9x + 43-4120 - 16 2 - 16 9 2 2 - 11 9 x +2 TX + 16 : A ( 92( 2) + B (-16) 92 2 16 - 16re Mathematics Year 2 (A Level) Tutor Card 1 Test Name: 3 For an arithmetic sequence a, = 98 and a,, = 56 a Find the value of the 20th term. (4 marks) b Given that the sum of the first n terms is 78, find the value of n. (4 marks) a4 : 98 21 : 56 n = at (n- 1) d aze = 198 + ( 20- 1 ) ed all : 567 ( 11-1)d * 117 66d 20-/117d - spid - 117 - 5x - 97 - 97 /= d Sn = In [za+ ( n- Dd ] 202 = at ( 20-1)d Sy = 1 x 4 [ 2 x 98 + ( 4-1) d]Pure Mathematics Year 2 (A Level) Tutor Card 1 Test Name: Andrey A B 1 Show that 6 (x+7) can be written in the form (5x-1)(2x +5) 5x - 1 2x +5 Find the values of the constants A and B. (5 marks) 6 ( 2( + 7 ) 5x - D ( 2 2+5 ) A + B ( 2 - 1) ( 2 215 ( (atD) A( 2x+5 ) + B(5x/ ) 620# 42 = 2 = 2.5 Bo= 17 57 57: HISB - 13. SB 27 : - 13.5 - 135 - 2 = BV x = 0.2 43.2 = S:4APure Mathematics Year 2 (A Level) Tutor Card 1 Test Name: 5 Given that in the expansion of - the coefficient of the x term is 75 find: ( 1 + ax) ? a the possible values of a (4 marks) b the corresponding coefficients of the x term. (2 marks) = ( 1+Q2 )-2 2)": I that h( n-1) 2 2 ! * + (m) ( h-1) (n-2) x3 +