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a=7 B= 2 2B.a=27.2 Question 5 Remark: 0: and ,6 are the last 2 digits of your SEGi student ID. Example 1: SUKDl23564789. then a

a=7 B= 2 2B.a=27.2

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Question 5 Remark: 0: and ,6 are the last 2 digits of your SEGi student ID. Example 1: SUKDl23564789. then a = 8. = 9 . Thus 2;} .a = 29.3. Example 2: SUKD123564709, then a! = U, ,3 = 9. Thus 2,6 .0: = 29.0. Example 3: SCM012546653, then a: 5, = 3 . Thus 2,133 -a = 23.5. INSTRUCTION: Write down the values of a , ,6 and 2 ,6 .a before solving the following questions. A study has been carried out on how does the shear resistance. 3: is affected by the normal stress, x of the metal tube. Table Q5 shows the coded observations. Table 05 x 26.2 25 23.2 24.5 20.4 22.4 23.4 25 .7 26.5 r 26.4 27.1 22.4 21.5 2 ,6 . a 26.4 21.3 26.6 25.4 (a) Construct the equation of the least squares linear regression. (10 marks) (b) Calculate the coefcient of determination for the data and interpret the calculated value. (8 marks) (c) Estimate the shear resistance when the normal stress is 26.3 and comment on the value found. (2 marks) (Total: 20 marks) ---END OF QUESTION PAPER-n

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