abletop. In Case 2 the string is pulled horizontally, parallel to the tabletop. In both cases the yoyo 18%) Problem 7: A yoyo is constructed by attaching three uniform, solid disks along their F :entral axes as shown. The two outer disks are identical, each with mass M = 5 7 g, radius R = 3.8 :m, and moment of inertia l/ZMIRz. The central, smaller disk has mass M2 and radius R/2. A light, :lexible string of negligible mass is wrapped counterclockwise around the central disk of the yoyo. Fhe yoyo is then placed on a horizontal tabletop and the string is gently pulled with a constant force R 5' = 0.275 N. The tension in the string is not sufcient to cause the yoyo to leave the tabletop. In this )roblem consider the two cases show. In Case 1 the string is pulled straight up, perpendicular to the l. R 'olls Without slipping. 2 F Uthccxpcrttaxum a V 25% Part (a) What is the moment of inertia [C M about the central axis (i.e. the axis perpendicular to the circular face) of the yoyo, in kg-mz. 10M: 8.74 * 10'5 ICM: 8.74E-5 J Correct! 3 :9 25% Part (D) In both cases shown, what is the magnitude of the torque 1: exerted by the string about the contact point of the yoyo with the table, in J-m? Er= 5.22 *10'3 = 0.00522 J Correct! 47 25% Part (c) What is the moment of inertia of the yo-yo about the contact point with the table, in kg-m2? = 2.92 * 10'4 = 2.92E4 J Correct! ; $3 25% Part (d) What is the magnitude of the linear acceleration of the center of mass of the yoyo the moment the string becomes taut, in m/sz. 7 Grade Summary aCM _ i Deductions 24% Potential 76% Submissions Attempts remaining: i ( per attempt) detailed View 1 4% A _ 2 4% @ Degrees O Radlans V0 BACKSPACE In CLEAR 3 4% 4 4% . Submit Hint Feedback I give up! Iints: L for a 0% deduction. Hints remaining: 1 Feedback: 0% deduction per feedback. Notice that the yoyo is not leaving the ground, so the acceleration of the center ufrnass is due to the angular acceleration around the point of rotation. iubmission History All Date time: are displayed in Central Standard Timeed ruhmusion date time: indicate [are work Date Time Answer Hints Feedback 1 Jun 19, 2022 5:59 PM aCM= 2.26 2 Jun 20, 2022 12:22 PM \"CM: 1.13 3 Jun 28, 2022 12:05 PM \"CM: 1 -Notice that the yo-yo is not leaving the ground, so the acceleration of the center of mass is due to the angular acceleration around the point of rotation. 4 Jun 28, 2022 12:34 PM \"CM: 7.4 5 Jun 28, 2022 1:51 PM \"CM: 0.13 6 Jun 28, 2022 1:54 PM \"CM: Note: Feedback not 03397 accessed. All contart Q 2022 Expert TA, LLC