Aboxcontains9twoinchscrews,ofwhich6haveaPhillipsheadand3havearegularhead.Supposethatyouselect3screwsrandomlyfromthebox.WhatistheprobabilitythattherewillbemorethanonePhillipsheadscrewunderawithoutreplacementscenario?

my work:

P(x > 1) = P(x = 2)+P(x = 3)

or

P(x > 1) = 1 - P(x=1)

n=3, p= 6/9= .6667

binomial distribution: P(X=x) = nCx (p^x) (1 - p)^n-x

P(x = 2) = 3C2(.6667^2)(1-.6667)^1 = .4444

P(x = 3) = 3C3(.6667^3)(1-.6667)^0= .2963 sum both = .7407

or

1 - P(x=1) = 1 - 3C1(.6667^1)(1-.6667)^2 = .7778

i am lost as to why I got 2 different answers here