Absorbance of iron$($III$)$ salicylate complex at $525$ nm$=1\mathrm{.}202$

Mass of crude product analyzed$=0\mathrm{.}023$g

Crude product dillutied twice $0\mathrm{.}023$g solid$/10$mL then $4$mL of that solution $+6$mL DI water$=10$mL solution

Calculate the $\%$ salicylic acid in your product. For full credit, be sure to neatly show all of the required work. What is the $\%$ impurity in your product?