According to a certainorganization, adults worked an average of 1,880 hours last year. Assume the population standard deviation is 43 hours and that a random sample of 50

adults was selected. Complete parts a through e below.

a. Calculate the standard error of the mean.

x=

(Round to two decimal places asneeded.)

b. What is the probability that the sample mean will be more than 1,890 hours?

P(x>1,890)=

(Round to four decimal places asneeded.)

c. What is the probability that the sample mean will be between1,830 and 1,870 ?

P1,830x1,870equals=

(Round to four decimal places asneeded.)

d. Would a sample mean of 1,910 hours support the claim made by theorganization? Select the correct choice below and fill in the answer box within your choice.

(Round to four decimal places asneeded.)

A The probability Px1,910= ______This contradicts the claim.

B.The probability Px1,910equals ____This supports the claim.

e. Identify the symmetrical interval that includes95% of the sample means if the true population mean is 1,880 hours.

____hoursx____hours

(Round to one decimal place asneeded.)