According to a recent study, the carapace length for adult males of a certain species of tarantula are normally distributed with a mean of $=17\mathrm{.}27mm$ and a standard deviation of $=1\mathrm{.}97mm.$ Complete parts $($a$)$ through $($d$)$ below.

Click here to view page $1$ of the standard normal distribution table.

Click here to view page $2$ of the standard normal distribution table.

a$.$ Find the percentage of the tarantulas that have a carapace length between $15mm$ and $16mm.$

The percentage of the tarantulas that have a carapace length between $15$ and $16$ is $\%.$

$($Type an integer or decimal rounded to two decimal places as needed.$)$