According to a study published in a reputable science magazine, about 6 women in 100,000 have cervical cancer (C), so P(C)equals=0.00006. Suppose the chance that a Pap smear will detect cervical cancer when it is present is 0.83. Therefore,Upper P left parenthesis test pos|C right parenthesisP(testpos|C)equals= What is the probability that a randomly chosen woman who has this test will both have cervical cancer AND test positive for it?