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According to the Centers for Disease Control, 31.6 % of American adults ages 20 and over suffer from hypertension. A sample of 101 adults were
According to the Centers for Disease Control, 31.6 % of American adults ages 20 and over suffer from hypertension. A sample of 101 adults were recruited to participate in relaxation training in hopes of lowering the incidence of hypertension. At the end of a year, the adults are re-evaluated and the proportion who suffer from hypertension is recorded.
- Completely describe the sampling distribution of the sample proportion of adults who suffer from hypertension when samples of size 101 are selected.Round any calculated values to four decimal places.
- mean:
- p
- p^
- =
- standard deviation:
- p
- p^
- =(round to 4 decimal places)
- np =and n(1 - p) =so the distribution of
- p
- p^
- is:Select an answer
- Not normally distributed
- Normally distributed
- According to the Empirical Rule, we expect 68 % of all samples of 101 adults to result in a sample proportion betweenandwith hypertension. Round your answers to 4 decimal places. (Hint:Draw the normal model based on the description in part a.)
- Suppose the sample of 101 adults participated in the relaxation training and returns a proportion of 0.2766 with hypertension. Does this sample proportion provide any support for the conjecture made?
- The sample proportion, 0.2766, is more than 3 standard deviations below the mean. This provides very strong support for the conjecture that relaxation training lowered the occurrence because it is highly unlikely to occur by chance alone.
- The sample proportion, 0.2766, is between 1 and 2 standard deviations below the mean. This provides some support for the conjecture that relaxation training lowered the occurrence, although it is not overwhelming.
- The sample proportion, 0.2766, is between 2 and 3 standard deviations below the mean. This provides strong support for the conjecture that relaxation training lowered the occurrence because it is unlikely to occur by chance alone.
- The sample proportion, 0.2766, is less than 1 standard deviation below the conjectured value. This would not provide strong support to the conjecture that relaxation training lowered the occurrence of hypertension.
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