Accounting for the inhibitor in the feed, evaluate whether the immobilized enzyme reaction is reaction- or diffusion- limited, & determine the rate of product formation (dp/dt) in mol/L-min that you would expect in the immobilized enzyme reactor.

on 8. (10 pts) An enzyme reaction is being made into a continuous process using immobilization. Data have been collected the unimmobilized and uninhibited system using 100% active enzyme, and are shown in an Eadie-Hofstee plot at right (the equation of the line is shown on the plot). Beads containing enzyme are placed in a continuous flow reactor where substrate enters at (S). = Sp = 0.468 M. v, mol/L-min Eadie-Hofstee Plot for Free Uninhibited Enzyme 0.045 0.04 0.035 0.03 0.025 y = -0.027x +0.044 0.02 0.015 0.01 0.005 0 0.5 1 v/[S], 1/min 0 1.5 2 S, E P, S, Immobilized enzyme reactor parameters: total bead surface area in the packed column 790 cm % active enzyme 82 mol % Reactor volume 2.5L Reaction Mechanism: S+E+1 ES-27E+P effective substrate diffusivity, Due 4.7. 10 cm/s Encapsulating membrane thickness, 6 12 um (1.2.10m) kinetic rate constants (kt, k., ka) are NOT given, nor is there any information about porosity or tortuosity Another challenge that your co-worker just reported is that the feed contains a non-competitive inhibitor, which cannot be removed from the substrate entering the reactor. The inhibitor, 10) = 0.0092 M, has dissociation constant, K = 0.034 M. Accounting for the inhibitor in the feed, evaluate whether the immobilized enzyme reaction is reaction or diffusion- limited, and determine the rate of product formation (dp/dt) in mol/L-min that you would expect in the immobilized enzyme reactor