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Acetylene burns in air according to the following equation: CH(g) + O(g) 2C0(g) + HO(g) kJ Given AH of CO(g)=-394.4 - and AH of
Acetylene burns in air according to the following equation: CH(g) + O(g) 2C0(g) + HO(g) kJ Given AH of CO(g)=-394.4 - and AH of HO(g)=-228.6 mol figures. kJ mol X AH-1256.2 kJ mol find AH of CH(g). Be sure your answer has the correct number of significant
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Chemistry For Engineering Students
Authors: Lawrence S. Brown, Tom Holme
4th Edition
0357026993, 978-0357026991
