After the conversion of the following $\backslash$epsi $-$NFA to the Non$-$deterministic Finite Automaton $($NFA$),$

If $\backslash$delta denotes the transition function of the final NFA, then in the final NFA:

$\backslash$delta $($q$2,$

$)=$q$0$

$\backslash$delta $($q$0,$

$)=$q$0$