All the answers, and please doble check before sending them to me. Thanks!
Test: Week 3 Test ... Question 19 This Test: 100 pts possible Submit Test The amounts (in oz) in cans of soda are given below. The cans are labeled to indicate that the contents are 12 oz of soda. Use a 0.05 significance level to test the claim that the cans are filled so that the median amount is 12 oz. If the median is not 12 oz, are consumers being cheated? Click the icon to view the data table. Click here to view page one of the standard normal distribution table. Click here to view page two of the standard normal distribution table. Amounts (in oz) in cans of a X First define the null and alternative hypotheses. certain soda Ho Volume Regular Soda 12.0 12.2 12.2 12.4 Calculate the Wilcoxon test statistic. 12.3 12.1 12.2 12.0 12.2 12.3 12.2 12.1 T = [ 12.3 11.9 12.4 12.2 12.2 12.2 12.2 11.9 Since the sample size n is greater than 30, convert T to a z test statistic. 12.2 11.8 12.1 12.4 12.1 12.0 12.1 12.4 2 =] 12.2 11.9 12.2 12.1 12.1 11.9 12.2 12.2 (Round to two decimal places as needed.) Determine the critical value(s). The critical value(s) is/are]. Print Done (Round to two decimal places as needed. Use a comma to separate answers as needed.) Choose the correct answer below. O A. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. O B. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. O C. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. O D. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. Are consumers being cheated? O A. Since the median of the sample is 12.2, there is no reason to suspect that consumers are being cheated. O B. Since the null hypothesis was not rejected, there is no reason to suspect that consumers are being cheated. O C. Since the median of the sample is 12.2, there is a reason to suspect that consumers are being cheated. O D. The sample mean is 12.0 oz