Alternative 1 has a useful life of 5years. The initial investment is $15,000 and the annual cost of operating the system is $6,000. The salvage value at the end of five years is $3,000. Alternative 2 has a useful life of three years. The initial investment is $20,000 and the annual operating expense is $2,000. It has no salvage value at the end of 3 years. MARR = 20% What is the AW2 - AW1 assuming repeatability?

So I understand this as you find PW and then find AW. Please choose from the following options...

		-$-478
		-$8,882
		-$882
		+$478