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Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)Al2(SO4)3(aq)+6H2O(l) How many moles of Al2(SO4)3 can form under these conditions? How many moles of the excess

Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)Al2(SO4)3(aq)+6H2O(l)

How many moles of Al2(SO4)3 can form under these conditions?

How many moles of the excess reactant remain after the completion of the reaction?

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