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AMA output force / input force Efficiency (AMA/IMA) x 100% IMA input force (g) output force (g) AMA Efficiency (%) input output distance distance
AMA output force / input force Efficiency (AMA/IMA) x 100% IMA input force (g) output force (g) AMA Efficiency (%) input output distance distance (cm) (cm) N.A. N.A. 1 500g 5009 2 2809 5309 3 2109 5309 10 4 1609 5309 10 N.A. N.A. Questions: 1) As the IMA increases, the efficiency should be decreasing. Why do you think this is so ? 2) When the IMA is 1, the load being lifted is the 500 gram weight. For the cases when the IMA is 2,3 and 4, the lower two pulleys are being lifted along with the 500 gram weight. In each of these three cases, what is the output force? 3) For IMA = 2, when the input distance is 10 cm, what is the output distance you measure? Is it approximately half the input distance? (it should be) 4) If a pulley system on the ceiling of the hangar has an AMA of 4, how much force would be needed to lift a small engine weighing 400 lb. 5) You should find that the AMA is always less than the IMA. Why?
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Solutions Step 1 To calculate the Ideal Mechanical Advantage IMA of a simple machine use the followi...Get Instant Access to Expert-Tailored Solutions
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