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An account was opened up 10 years ago and $500 was deposited at the beginning of each month for 3 years, followed by deposits of

  1. An account was opened up 10 years ago and $500 was deposited at the beginning of each month for 3 years, followed by deposits of $1000 at the beginning of each month for 2 years. The account earns interest at j12 = x%. The accumulated value of the account today is $63,450.00. Solve for j12 using linear interpolation.

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