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An amusement park ride is designed to move passengers up and down, including downward acceleration greater than g (so-called negative g's). This is done

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An amusement park ride is designed to move passengers up and down, including downward acceleration greater than g (so-called "negative g's"). This is done by having cables connected to both the top and bottom of the ride that work together to give the desired upwards and downwards accelerations. Define upwards as the positive y direction. Let the mass of the ride, including passengers, be M = 1,407 kg. During the ride the acceleration is downwards: a = = - 1.27 g (where, of course, g = 9.8 m/s) If the tension in Cable 1 is FT1 = 0.57 M g (M g is, of course, the weight of the ride meaning the force of gravity on the ride) what is the magnitude of the tension in Cable 2? Give your answer in Newtons to at least three significant digit to avoid being counted off due to rounding. Do not include the units (N) in your answer. Cable 1 Cable 2

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