an can A toboggan is traveling down along a curve which be approximated by the parabola y = 0.01x2 Determine the magnitude of its acceleration when it reaches point A, where its speed is = 10 m/s, and it is increasing at the rate of (a) 3 m/s. = a = ? 36 m 7901 y = 0.012 V=0,02x m/s a=0,02 m/s =? je. ppro oving system ment of the 2/18, point, system, in for posit 60 m Acceleration: The radius of curvature of the path at point A must be determined dy first. Here, = 0.02x and d'y = 0.02, then dx a dx V p = [1 + (dy/dx)213/2 \dy/dx = (0,02.60) x=60 m 190.57 m 4R =72 0102 [1+ (0.02x)213/2 | 10.02| To determine the normal acceleration, apply Eq. 12-20. 10 an = 0.5247 m/s P 190.57 Here, a, = v = 3 m/s. Thus, the magnitude of accleration is a = - Va + an +a= 3 + 0.5247 = 3.05 m/s Ans. B A A/B, an o rea g syst ovin lica ns ay a e