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An electric charge of Q = 1.60 10 4 C is distributed uniformly along a rod of length 2 L , extending from y =
An electric charge of Q = 1.60 104 C is distributed uniformly along a rod of length 2L, extending from y = -26.0 cm to y = +26.0 cm, as shown in the diagram above. A charge q = 2.25 106 C, and the same sign as Q, is placed at (D,0), where D = 19.5 cm. Integrate to compute the total force on q in the x-direction.
can you please show me the steps to solve this. Thank you!!!
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