Question
An equimolar liquid mixture and benzene is separated into two products by distillation. Inside the column a liquid stream flows downward and a vapor stream
An equimolar liquid mixture and benzene is separated into two products by distillation. Inside the column a liquid stream flows downward and a vapor stream rises. At each point in the column some of the liquid vaporizes and some of the vapor condenses. The vapor leaving the top of the column, which contains 97 mole% benzene, is completely condensed and split into two equal fractions: one is taken off as the overhead product stream, and the other (the reflux) is recycled to the top of the column. The overhead product stream contains 89.2% of the benzene fed to the column. The liquid leaving the bottom of the column is fed to a partial reboiler in which 45% of it is vaporized. The vapor generated in the reboiler (the boil-up) is recycled to become the rising vapor stream in the column, and the residual reboiler liquid is taken off as the bottom product stream. The compositions of the streams leaving the reboiler are governed by the relation
[yB(1-yB)]/[xB(1-xB)]=2.25
where and are the mole fractions of benzene in the vapor and liquid streams, respectively. Take a basis of 100 mol fed to the column, determine the following:
1) the molar amounts of overhead and bottom products
a) 46 mol and 54 mol
b) 49 mol and 51 mol
c) 33 mol and 67 mol
d) 38 and 62 mol
2) the mole fraction of benzene in the bottom product
a) 0.2
b) 0.3
c) 0.4
d) 0.1
3) the percentage recovery of toluene in the bottoms product
a) 92%
b) 97%
c) 95%
d) 90%
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started