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An image is taken using 90 kVp, and 12 mAs, and produces a quality image. A new image is taken using 110 kVp at 30
An image is taken using 90 kVp, and 12 mAs, and produces a quality image. A new image is taken using 110 kVp at 30 mAs, and an SID of 50 cm. What was the original SID if the 2 images maintained the same exposure? (I think this is the mAs/Distance formula)
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