An MBA director examined GMAT scores for the first 10 MBA applicants (assumed to be a random sample of early applicants) for four academic quarters. Research question: Is there a difference in the means among these four quarters?

GMAT Scores of First Ten Applicants

Fall 490 580 440 580 430 420 640 470 530 640

Winter 310 590 730 710 540 450 670 390 500 470

Spring 500 450 510 570 610 490 450 590 640 650

Summer 450 590 710 240 510 670 610 550 540 540

Click here for the Excel Data File

Fill in the missing data. (Round intermediate calculations to 2 decimal places. Round your mean values to 1 decimal place, MS values to 3 decimal places, F and p-values to 4 decimal places, and other answers to 2 decimal places.)

Table of Means

Group Mean n Std. Dev Variances

Fall 522 522 Correct 10 10 Correct 84.30 84.30 Correct 7,106.49 7,106.49 Correct

Winter 536 536 Correct 10 10 Correct 139.14 139.14 Correct 19,359.94 19,359.94 Correct

Spring 546 546 Correct 10 10 Correct 75.45 75.45 Correct 5,692.70 5,692.70 Correct

Summer 541 541 Correct 10 10 Correct 130.08 130.08 Correct 16,920.81 16,920.81 Correct

Total 536.30 536.30 Correct 40 40 Correct 106.81 106.81 Correct

One-Way ANOVA Table

Source SS df MS F p-value

Treatment 3207.50 3207.50 Correct 3 3 Correct 1,069.167 1,069.167 Correct 0.0871 0.0871 Correct .9666 .9666 Correct

Error 441,730.00 441,730.00 Correct 36 36 Correct 12,270.278 12,270.278 Correct

Total 444,937.50 444,937.50 Correct 39 39 Correct

Based on the hypotheses given below, choose the correct option.

H0: 1 = 2 = 3= 4

H1: Not all the means are equal

= .05

Reject the null hypothesis if p-value < 0.05

Reject the null hypothesis if p-value > 0.05

On the basis of the above findings, we cannot reject the null hypothesis.

True

False

Based on the hypotheses given below, choose the correct option.

H0: 21 = 22 = 23 = 24

H1: Not all the variances are equal

= .05

Reject the null hypothesis if H > 6.31

Reject the null hypothesis if H < 6.31

Calculate the value of Hcalc. (Round your answer to 3 decimal places.)

Hcalc

On the basis of the above-determined Hcalc, we fail to reject the null hypothes