An SAT prep course claims to improve the test score of students. The table below shows the scores for seven students the first two times they took the verbal SAT. Before taking the SAT for the second time, each student took a course to try to improve his or her verbal SAT scores. Do these results support the claim that the SAT prep course improves the students' verbal SAT scores?

Let d=(verbalSATscorespriortotakingtheprepcourse)(verbalSATscoresaftertakingtheprepcourse)d=(verbalSATscorespriortotakingtheprepcourse)(verbalSATscoresaftertakingtheprepcourse). Use a significance level of =0.01 for the test. Assume that the verbal SAT scores are normally distributed for the population of students both before and after taking the SAT prep course.

Student	1	2	3	4	5	6	7
Score on first SAT	470	470	510	410	400	390	530
Score on second SAT	500	490	580	490	420	430	590

Step1of5: State the null and alternative hypotheses for the test.

Step 2 of 5: Find the value of the standard deviation of the paired differences. Round your answer to two decimal places.

Step 3 of 5: Compute the value of the test statistic. Round your answer to three decimal places.

Step 4 of 5: Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to three decimal places.

Step 5 of 5: Make the decision for the hypothesis test.

Reject Null Hypothesis Fail to Reject Null HypothesisCar Without additive With additive