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and mass number A: 43=0.714, 04 = 23.2, and Exercise 2.10: The semi-empirical mass formula approximate nuclear binding energy B of an atomic nucleus with

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and mass number A: 43=0.714, 04 = 23.2, and Exercise 2.10: The semi-empirical mass formula approximate nuclear binding energy B of an atomic nucleus with atomic number Z In nuclear physics, the semi-empirical mass formula is a formula for calculating the where, in units of millions of electron volts, the constants are a = 15.8, 22 = 18.3, d) Modify your program again so that, instead of taking Z as input, it runs through one. At what value of Z does the maximum binding energy per nucleon occur? (The true answer, in real life, is Z=28, which is nickel.) Z2 (A-22) B = a1 A - Q2A2/3 - 23 A1/3-24 + as A1/2' if A is odd, 45 = 12.0 if A and Z are both even, -12.0 if A is even and Z is odd. a) Write a program that takes as its input the values of A and Z, and prints out the binding energy for the corresponding atom. Use your program to find the binding energy of an atom with A = 58 and Z = 28. (Hint: The correct answer is around 500 MeV.) b) Modify your program to print out not the total binding energy B, but the binding energy per nucleon, which is B/A. c) Now modify your program so that it takes as input just a single value of the atomic number Z and then goes through all values of A from A = Z to A = 32, to find the one that has the largest binding energy per nucleon. This is the most stable nucleus with the given atomic number. Have your program print out the value of A for this most stable nucleus and the value of the binding energy per nucleon

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