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Anna and Tom run a key exchange protocol similar to Diffie-Hellman, but using Elgamal. In the protocol, both Anna and Tom agree on a group

Anna and Tom run a key exchange protocol similar to Diffie-Hellman, but using Elgamal.

In the protocol, both Anna and Tom agree on a group described by (p, q, g) . Then Anna chooses a random number xa Zq as her private key, and computes ha = gxa mod p. Tom chooses a random number xb Zq as his private key, and computes hb = gxb mod p. They give ha, hb to each other through a secure, out-of-band channel.

To establish a shared key, they do the following:

  1. Anna chooses a random number ka, encrypts it under Elgamal using Tom's public key (p, q, g, hb), the resulting ciphertext is (gra, gka hbra), and the ciphertext is sent to Tom.
  2. Tom chooses a random number kb, encrypts it under Elgamal using Anna's public key (p, q, g, ha) , the resulting ciphertext is (grb , gkb harb), and the ciphertext is sent to Anna.
  3. Anna decrypts to get gkb , and computes (gkb)ka gkakb mod p as the shared key.
  4. Tom decrypts to get gka , and computes (gka)kb gkakb mod p as the shared key.

Yes/No, is the man-on-the-middle attack in the Diffie-Hellman protocol still possible?

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