Question
Anova Two-Factor With Replication SUMMARY 3MM. 4MM. TOTAL 145 ___________________________________________________________ COUNT 6 6 12 SUM 57.89 56.66 114.55 AVERAGE 9.6483 9.4433 9.5458 VARIANCE 0.6445 1.8431
Anova Two-Factor With Replication
SUMMARY 3MM. 4MM. TOTAL
145
___________________________________________________________
COUNT 6 6 12
SUM 57.89 56.66 114.55
AVERAGE 9.6483 9.4433 9.5458
VARIANCE 0.6445 1.8431 1.1422
155
__________________________________________________________
COUNT 6 6 12
SUM 64.1 58.62 122.72
AVERAGE 10.6833 9.7700 10.2267
VARIANCE 3.3687 2.7493 3.00084
TOTAL
__________________________________________________________
COUNT 12 12
SUM 121.99 115.28
AVERAGE 10.1658 9.6067
VARIANCE 2.1163 2.1166
SOURCE OF VARIATION SS df MS F P- VALUE F CRIT
___________________________________________________________________________________________________
SAMPLE 2.7812 1 2.7812 1.2927 0.2690 4.3512
COLUMNS 1.8760 1 1.8760 0.8720 0.3615 4.3512
INTERACTION 0.7526 1 0.7526 0.3498 0.5608 4.3512
WITHIN 43.0284 20 2.1514
TOTAL 48.4382 23
At the 0.05 level of significance,
a.Is there aninteractionbetween the temperature and die diameter?
Null hypothesis
Alternative hypothesis
Decision
Conclusion
b. Is there an effect due todie temperature?
Null hypothesis
Alternative hypothesis
Decision
Conclusion
c. Is there an effect due todie diameter?
Null hypothesis
Alternative hypothesis
Decision
Conclusion
e. What conclusion can you draw from your analysis (overall conclusion)?
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