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ANSWER ALL 5 AND INCLUDE EXCEL SCREENSHOTS / HOW YOU DID IT (THE CODE AS WELL). SHOW ALL WORK. Questions: 1. identify and name random

ANSWER ALL 5 AND INCLUDE EXCEL SCREENSHOTS / HOW YOU DID IT (THE CODE AS WELL). SHOW ALL WORK.

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Questions:

1. identify and name random and non-random variables along the way. You may develop a flowchart for yourself to help you visualize.

2. List all random variables, their distributions, and parameters.

3. List all random variables, their distributions, and parameters.

4. What is the weekly average cost of all claims?

5. Suppose that the company decides to keep $15,000 cash on hand to pay claims. What is the probability that this amount will not be adequate to cover claims in any given week?

Vinton Auto Insurance is deciding how much money to keep in its checking accounts to cover insurance claims. In the past, the company held some of the premiums it received in interest-bearing checking accounts and put the rest into investments that are not quite as liquid, but tend to generate a higher investment return. The company wants to study cash flows to determine how much money it should keep in its checking accounts to pay claims. There are two types of claims: "repair" claims, and "totaled" claims. After reviewing historical data, the company has determined that the number of repair claims filed each week is a random variable that follows the probability distribution shown in the following table: #Repair Claims Probability 5 0 1 2 3 4 6 7 8 9 10 0.030 0.106 0.185 0.216 0.189 0.132 0.077 0.039 0.017 0.007 0.002 The company has also determined that the average cost per repair claim is normally distributed with a mean of $1,200 and standard deviation of $300 (with no negative values). To be clear, the costs of covering of each individual repair claim are not normally distributed; rather, the average cost per repair claim for a given week is normally distributed with a mean of $1,200 and a standard deviation of $300. In addition to repair claims, the company also receives claims for cars that have been "totaled" and cannot be repaired. There is a 15% chance of receiving one claim of this type in any week, and there is no chance of receiving more than one in any week. The cost for "totaled" cars is given by the following: $7500 X, where X is a log-normal random variable with a mean parameter of 0.1 and a standard deviation parameter of 0.5. Vinton Auto Insurance is deciding how much money to keep in its checking accounts to cover insurance claims. In the past, the company held some of the premiums it received in interest-bearing checking accounts and put the rest into investments that are not quite as liquid, but tend to generate a higher investment return. The company wants to study cash flows to determine how much money it should keep in its checking accounts to pay claims. There are two types of claims: "repair" claims, and "totaled" claims. After reviewing historical data, the company has determined that the number of repair claims filed each week is a random variable that follows the probability distribution shown in the following table: #Repair Claims Probability 5 0 1 2 3 4 6 7 8 9 10 0.030 0.106 0.185 0.216 0.189 0.132 0.077 0.039 0.017 0.007 0.002 The company has also determined that the average cost per repair claim is normally distributed with a mean of $1,200 and standard deviation of $300 (with no negative values). To be clear, the costs of covering of each individual repair claim are not normally distributed; rather, the average cost per repair claim for a given week is normally distributed with a mean of $1,200 and a standard deviation of $300. In addition to repair claims, the company also receives claims for cars that have been "totaled" and cannot be repaired. There is a 15% chance of receiving one claim of this type in any week, and there is no chance of receiving more than one in any week. The cost for "totaled" cars is given by the following: $7500 X, where X is a log-normal random variable with a mean parameter of 0.1 and a standard deviation parameter of 0.5

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