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Refer to Sections 1 and 4 in the course notes The slope of the tangent line to y = x2 at the point (, 312) is (enter answer in decimal form): Your Answer: :] Answer Question 2 (10 points) Refer to Section 4 in the course notes The slope of the curve to y=x4 at the point where x=3 is: Your Answer: :] Answer A particle moves along a line. Its distance from the starting point after t minutes is shown in the graph. d DISTANCE (in feet) ' C A 1 TIME [in minutes) ' Put in size order, smallest to largest , the speed of the particle at points A, B, C, so 1 denotes the slowest point and 3 denotes the fastest Question 4 (10 points) Refer to Sections 3 and 6 in the course notes If 7 3h dy yx+tendx Your Answer: :] Refer to the boxed comment in Section 5 of the course notes The function y=f(x) satisfies f(3) =7 and f '(3)=2. The equation of the tangent line to y=f(x) at the point x=3 (in y=mx+b form, no extra spaces or punctuation) is: :] '5' Question 6 (10 points) Refer to the boxed reminder at the end of Section 5 of the course notes. The graph below shows y=f(x) (red graph) and y=f '(x) (blue graph) as indicated. Find the equation of the tangent line to y=f(x) at the point where x=1. Enter your answer in y=mx+b form. DO NOT enter any extra spaces or symbols Question 7 (10 points) Refer to the boxed comments. Enter T for True and F for False The tangent line to y=f(x) at the point where x=a goes through the point (a,f(a)). [:~ The tangent line to y=f(x) at the point where x=a has slope f '(a) :M Question 8 (30 points) You may use / to indicate a fraction or handwrite your work and upload a picture. 1) Refer to Section 4 of the course notes. Compute the derivative ofy = 2+4 and show your work. 2) Refer to Sections 4 and 6 in the course notes. Find the equation of the tangent line toy = V; at the point (16,4) and show your work. Your answer should be in y=mx+b form. Paragraph