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answer the following A population of 100 rabbits can be modeled by the equation y = 100e-0.12, where y is the final population of rabbits,
answer the following
A population of 100 rabbits can be modeled by the equation y = 100e-0.12, where y is the final population of rabbits, x is the time in years. | 1400 1300 Graph 1 1200 1100 -1000 900 Graph 2 Number of Rabbits -800 700 600 -500 400 300 -200 1400 25 30 -25 -20 -15 -10 10 15 20 -100 Time in Years -200 -300 -400Which of the following equations could describe the graph below? (1,0) log a O (3) O log3 XNuml 700 600 500 400 300 200 -100 -2 00 -300 -400 10 15 20 Time in Years Which graph correctly models this population, and what ls the approximate number of rabbits in the population after 5 years? Graph 2 and there would be approximately 182 rabbits. Graph 2 and there would be approximately 100 rabbits. Graph 1 and there would be approximately 100 rabbits. Graph 1 and there would be approximately 54 rabbits. 25 30 Evaluate log7 37 to two decimal places: O 0.72 O 0.54 1.86 O 0.22 What is the exact value of the exponential equation, 4(10) 5x = 200? log50 O X= log5 log196 Ox = 5 log200 Ox= log50 5 The number of hours, t, that bacteria spread 10-fold can be modeled by the equation B(t) = B. (10)4. There are 50 bacteria present initially and a biologist wishes to find out how many hours will elapse until there are 10,000 bacteria present. What is the exact value for the number of hours elapsed, t, in the equation 10, 000 = 50(10)# O t = log 200 O t= log 200 log 4 O t = log 20 Ot= log 5,000 4 log 25010go (v2+5) - 10go (1845) is equivalent to O -4 0 4 O + O 4v When solving the logarithmic equation log(x - 5) + log(x + 4) = 1 for x, the solution is x = 0 and an extraneous solution is * * 0. O 6, -5 O -5,-6 O 6, 5 O -5, 6Step by Step Solution
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