Answer the following question. Up to 6 decimal places only. An experiment on college students is being conducted to find out how they fare on social acceptability. The study separated the males from the females to determine if gender differences have an effect on social acceptability.Compute the appropriate t test and p value. Significance Level at 5%, One tailed. Males 70 65 73 97 98 91 75 85 67 62 Females 87 98 79 95 93 96 79 85 89 97 1.) t score (2 pts) = 2.) p value (1 pt) = CheckTake a dependent samples t-test data below of patients with blood pressures before and after a sample medicine: Before After d d2 180 160 20 400 170 165 5 25 190 180 10 100 200 180 20 400 210 200 10 100 165 140 25 625 200 195 5 25 Use the formula: J r = bum/H Where 5 = sample mean difference n = number of sample mean differences sa = standard deviation of the sample differences Using the formula above, it will give us t = 13.57/[8.o1N7) t = 4.478 Considering the data above, it will give us a p value of 0.004200 making our result signicant at 0.05% level which means that the medication applied in the experiment has an effect on the test subjects. Try to find a significant difference in grades with a significan For this t-test, use the following equation: X1 - X2 S1 N2 Where x1 and x2 = mean for the two groups S12 and S22 = variances for the two groups N1 and N2 = number of participants per group The computation for the 2 samples would be as follows: t= (77.7-85.2) / V((131.12/10) + (85.96/10)) t= -1.60973 The p value for this is .062427 which is not significant at p