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Answer the following questions based on your knowledge of exception handling: Rewrite the following inefficient java code snippet to handle the runtime exception without using
Answer the following questions based on your knowledge of exception handling:
Rewrite the following inefficient java code snippet to handle the runtime exception without using exception handler. (Hints: use conditional expression to skip any runtime exception)
public static void main(String[] args) { methodl(); } private static void method1() { try { int[] arr = {1, 2, 0}; String[] result = new String[4]; result[1] = "a"; result[2] = ""; for(int i=0; i 0 && result[i].equals(i+1)) { System.out.println("Okay"); } else { System.out.println("Not Okay"); } } } catch (Exception e) { System.out.println(el); } }Step by Step Solution
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